
Dated=newDate(0);34.Stringds=December15,2004”;35.//insertcodehere36.try{37.d=df.parse(ds);38.}39.catch(ParseExceptione){40.System.out.println(”Unabletoparse+ds);41.}42.//insertcodeheretooWhichwillcreatetheappropriateDateFormatobjectandaddadaytotheDateobject?() A. 35.DateFormatdf=DateFormat.getDateFormat();42.d.setTime((60*60*24)+d.getTime()); B. 35.DateFormatdf=DateFormat.getDateJnstance();42.d.setTime((1000*60*60*24)+d.getTime()); C. 35.DateFormatdf=DateFormat.getDateFormat();42.d.setLocalTime((1000*60*60*24)+d.getLocalTime()); D. 35.DateFormatdf=DateFormat.getDateJnstance();42.d.setLocalTime((60*60*24)+d.getLocalTime());
To solve this problem, we need to correctly create a DateFormat object to parse the string "December15,2004" and then add one day to the resulting Date object. Here's the breakdown:
Creating the DateFormat Object:
The correct method to obtain a standard date formatter in Java is DateFormat.getDateInstance(), not getDateFormat() (which is not a standard method). This eliminates options A and C.
Adding One Day to Date:
The Date class uses milliseconds since the Unix epoch (January 1, 1970). To add one day, we need to calculate the millisecond equivalent of 24 hours: 1000 ms/sec × 60 sec/min × 60 min/hr × 24 hr/day = 86,400,000 ms. The Date class provides setTime(long milliseconds) and getTime() methods to manipulate time in milliseconds. Methods like setLocalTime() or getLocalTime() do not exist in the standard Date class, eliminating options C and D.
Line 35: Use DateFormat.getDateInstance() to create a valid date formatter.
Line 42: Add 86,400,000 milliseconds (1 day) to the parsed date using d.setTime(1000*60*60*24 + d.getTime()).
Answer: B
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